Is 1 = 0.9999......

[jinduy]

to celebrate my 1000th post, i'd like to resurrect this post and say that (barney the dinosaur voice) 2 + 2 is 4!

 

[Kyteland]

Originally posted by: jinduy
to celebrate my 1000th post, i'd like to resurrect this post and say that (barney the dinosaur voice) 2 + 2 is 4!

2 + 2 = 5

(For large values of 2 and small values of 5)

 

[bleeb]

Originally posted by: Kyteland

Originally posted by: jinduy
to celebrate my 1000th post, i'd like to resurrect this post and say that (barney the dinosaur voice) 2 + 2 is 4!

2 + 2 = 5

(For large values of 2 and small values of 5)

Aye Dios Mio!

 

[bleeb]

Hey Kyteland...

You got ambitions to have this thread go to 2K posts??

 

[FelixDeCat]

Mods can we get a lock on this one?

 

[Kyteland]

Originally posted by: bleeb
Hey Kyteland...

You got ambitions to have this thread go to 2K posts??

1,000,000 posts!
</Dr. evil>

 

[Koing]

lol this AGAIN

KOing

 

[eakers]

i like this thread.

 

[bleeb]

Originally posted by: eakers
i like this thread.

Yeah I feel very fondly of it too.

 

[esun]

Yes. Think of it this way: if those 9's in the x = 0.999... end at any point, then the answer is no. This is because at the point 10x - x = 9.999... - 0.999... becomes, for example, 10x - x = 9.999 - 0.99 (those nines continue for however long, but are always off by one), thus making the expression not exactly equal to 9. However, since according to this question they do continue forever, then those repeating nines all cancel each other out, therefore making the expression true.

 

[MadRat]

Originally posted by: esun
Yes. Think of it this way: if those 9's in the x = 0.999... end at any point, then the answer is no. This is because at the point 10x - x = 9.999... - 0.999... becomes, for example, 10x - x = 9.999 - 9.99 (those nines continue for however long, but are always off by one), thus making the expression not exactly equal to 9. However, since according to this question they do continue forever, then those repeating nines all cancel each other out, therefore making the expression true.

Nonsense. The division never occurs in the first place because there is no practical way to represent the operation without voodoo math.

 

[johneetrash]

[triumph] YOU ARE (all) A HUGE NERD [/triumph]

 

[TechnoKid]

Originally posted by: bleeb

Originally posted by: eakers
i like this thread.

Yeah I feel very fondly of it too.

this thread is long

 

[bleeb]

Originally posted by: TechnoKid

Originally posted by: bleeb

Originally posted by: eakers
i like this thread.

Yeah I feel very fondly of it too.

this thread is long

Out of the deeps of ATOT archiving, its BACK!

0.9999... != 1!

 

[pkananen]

any competant (sp?) math prof. will tell you it does indeed equal 1

 

[geno]

make it stop, please, just make it go away

 

[ryzmah]

Originally posted by: pkananen
any competant (sp?) math prof. will tell you it does indeed equal 1

Any competent math prof wouldn't use the questionable notation of .9999....; they would use an infinite sum which would allow them to prove it with a standard epsilon/delta proof.

 

[TravisT]

This is not true..... .9999999 does not equal 1

Even in a real life scenario. If you shoot a rocket to the moon, or better yet, pluto. The angle of your rocket is set at 1... you fire the rocket and it hits pluto. Then you reset the rocket at an angle of .999999999 (When in real life you can not set an infinite, however, you would have to stop somewhere.... Your rocket may still hit but it would be a significant difference from the first one fired. No?

 

[Jzero]

Are you guys still here????

 

[Hector13]

Originally posted by: ryzmah

Originally posted by: pkananen
any competant (sp?) math prof. will tell you it does indeed equal 1

Any competent math prof wouldn't use the questionable notation of .9999....; they would use an infinite sum which would allow them to prove it with a standard epsilon/delta proof.

what difference does the notation make??

 

[imported_Papi]

im pretty sure this is a repost.

 

[DivideBYZero]

Originally posted by: yayo
im pretty sure this is a repost.

No. It's just older than the Internet itself.

 

[Eli]

:Q

 

[dman]

I was watching Star Wars Episode .99999999999999999... the other day and I got to thinking,
this thread is too long.

 

[ryzmah]

Originally posted by: Hector13

Originally posted by: ryzmah

Originally posted by: pkananen
any competant (sp?) math prof. will tell you it does indeed equal 1

Any competent math prof wouldn't use the questionable notation of .9999....; they would use an infinite sum which would allow them to prove it with a standard epsilon/delta proof.

what difference does the notation make??

Infinite sums are well defined in mathematics and a proof can be traced back to the base assertions of set theory or potentially category theory. .... is not well defined. If you can't clearly define something in mathematical terms you can't trace a proof back to fundamental axioms - you would have to make an axiom to define ... and your definition makes the answer useless for proof unless it's accepted by those you're trying to convince. Half the challenge in modern algebra and real analysis is making sure everything you use is well defined.