Is 1 = 0.9999......

[mchammer187]

Originally posted by: cheapbidder01

Originally posted by: mchammer187

Originally posted by: Shanti
Everyone who's taken calculus should know that it approaches one but isn't equal to one.

everyone who has taken calculus and UNDERSTOOD it would realize that .9999...... is not a limit thus it cannot approach anything other than what it is 1

plot y= .999999999999999999.............. if it has a different value @ x = infinity than x=0 something is seriously wrong

You didn't understand calculus did you. You didn't do your plot right either, if you didn't get Y=1 for any X.

I understood calc very well thank you

y = 1 for all values of x thus it does not approach anything that it already is for ALL VALUES

 

[AgaBoogaBoo]

I'm glad I haven't ever tried reading this thread, if I did, it would take many hours to catch up, I haven't even read the first page :Q

 

[silverpig]

Originally posted by: RossGr

9 + .09 + .009 + ... = Sum N{1,M} [9*.1^N] = B

I disagree. you have presened a recognizable pattern followed by an ellipsis. This means I should continue the pattern infinitly. What you have represented is = .999... . The sum does not terminate at some unspecificed M, it continues to infinity.

How then would you write Sum N{1,M} [9*.1^N] in discrete terms? .9 + .09 + .009 + ... + .{M-1,0}9?

The only time I use an ellipsis to refer to infinity is as in 0.999... otherwise it makes sense to have it mean some arbitrary number. Very formally you can't have a sum of an infinite number of terms, but only a limit of an arbitrary number of terms as that arbitrary upper limit approaches infinity. ie:

Sum N{1,inf} x

is just informal shorthand for

lim m->inf Sum N{1,m} x

Either way though, this is just a matter of notation and not of real mathematical substance. The final point is that the number 0.999... is the limit of the sum, and is equal to 1. Notation aside, the ideas are there.

 

[silverpig]

Originally posted by: mchammer187

Originally posted by: Shanti
Everyone who's taken calculus should know that it approaches one but isn't equal to one.

everyone who has taken calculus and UNDERSTOOD it would realize that .9999...... is not a limit thus it cannot approach anything other than what it is 1

plot y= .999999999999999999.............. if it has a different value @ x = infinity than x=0 something is seriously wrong

It IS a limit dude. A limit is a number, an infinite sum is a progression. The limit is 1 and cannot change. To paraphrase a funny joke:

lim m->inf Sum N{1,m} 9*.1^N = 1, even for small values of infinity.

 

[mchammer187]

Originally posted by: silverpig

Originally posted by: mchammer187

Originally posted by: Shanti
Everyone who's taken calculus should know that it approaches one but isn't equal to one.

everyone who has taken calculus and UNDERSTOOD it would realize that .9999...... is not a limit thus it cannot approach anything other than what it is 1

plot y= .999999999999999999.............. if it has a different value @ x = infinity than x=0 something is seriously wrong

It IS a limit dude. A limit is a number, an infinite sum is a progression. The limit is 1 and cannot change. To paraphrase a funny joke:

lim m->inf Sum N{1,m} 9*.1^N = 1, even for small values of infinity.

ok it technically is a limit

in the sense that (limit 2) = 2 as x -> any number

i was just trying to say the value of .999999999999999999999999 does not change for any value of X so therefore it does not approach anything

or it does in the sense that y = 2 approaches 2 for all values of x but that still means it holds the same value everywhere

 

[bleeb]

If 1 = 0.99999... then why don't we see more 0.9999... McValue meals at McDonalds? Or 0.9999.. deals elsewhere? Since they are the same, shouldn't we see more 0.9999.. deals going???

0.9999... != 1!

 

[bigredguy]

FOR THE LOVE OF GOD LET THIS DIE. I BEG ALL OF YOU TO NEVER POST HERE AGAIN. My $.02

 

[Chu]

Originally posted by: bleeb
If 1 = 0.99999... then why don't we see more 0.9999... McValue meals at McDonalds? Or 0.9999.. deals elsewhere? Since they are the same, shouldn't we see more 0.9999.. deals going???

0.9999... != 1!

For the same reason you don't see "Now on sale! New value meals for only -(($0.01)^-100)-1.99 cents! We like nice round numbers because our brain is better equipped to deal with them. In the sciences you run into limits all over the place, and the whole argument we are having about 0.9999=1 is based on people not understanding what limits are.

-Chu

 

[79Blazer]

STFU!

 

[Ketteringo]

Originally posted by: fermium
STFU!

What a nef.

 

[79Blazer]

Originally posted by: Ketteringo

Originally posted by: fermium
STFU!

What a nef.

Pot. Kettle. Black.

 

[bandana163]

Pecan pie.

 

[Kyteland]

Originally posted by: bleeb
If 1 = 0.99999... then why don't we see more 0.9999... McValue meals at McDonalds? Or 0.9999.. deals elsewhere? Since they are the same, shouldn't we see more 0.9999.. deals going???

0.9999... != 1!

Man Bleeb. if you keep bumping this post there's going to be a ATOT lynching.

"String him up, and make sure the rope is 0.9999.... feet long!!"

I don't know about you, but I've had the 0.9999... McValue meal before. You must go to the wrong McDonalds if you've never had it.

 

[BigToque]

Theoretically, 1 != .999...
Practically, 1 = .999...

I can't imagine some carpenter saying "Damnit Jim, you cut the fscking board to short! I said 1 meter, not .999999999999999999999999999999999 meters! Get it right!

How this reached 1900 posts is beyond me.

 

[jurzdevil]

Originally posted by: bigredguy
FOR THE LOVE OF GOD LET THIS DIE. I BEG ALL OF YOU TO NEVER POST HERE AGAIN. My $.02

you mean your $.019999999999999999999999999999999999999999999999999

 

[parsley007]

no

 

[MAME]

Originally posted by: Stefan
Theoretically, 1 != .999...
Practically, 1 = .999...

you are wrong. prove this statement

 

[MAME]

Originally posted by: bleeb
If 1 = 0.99999... then why don't we see more 0.9999... McValue meals at McDonalds? Or 0.9999.. deals elsewhere? Since they are the same, shouldn't we see more 0.9999.. deals going???

0.9999... != 1!

you can't be serious

 

[BigToque]

Originally posted by: MAME

Originally posted by: Stefan
Theoretically, 1 != .999...
Practically, 1 = .999...

you are wrong. prove this statement

X = .999999999999999

1 - X = .000000000000001
1 - 1 = 0

.000000000000001 != 0

therefore X != 1

therefore .999999999999999 != 1

You can't look at it any other way. The 2 numbers are not the same.

I don't want to start talking about limits.

 

[Kyteland]

Originally posted by: Stefan
I don't want to start talking about limits.

Then you must not want to start talking about 0.9999... because 0.99999999999999999999999999999999999999999 != 0.9999...

 

[MAME]

Originally posted by: Stefan

Originally posted by: MAME

Originally posted by: Stefan
Theoretically, 1 != .999...
Practically, 1 = .999...

you are wrong. prove this statement

X = .999999999999999

1 - X = .000000000000001
1 - 1 = 0

.000000000000001 != 0

therefore X != 1

therefore .999999999999999 != 1

You can't look at it any other way. The 2 numbers are not the same.

I don't want to start talking about limits.

congradulations! You proved that .999999999999999 != 1


THAT'S AMAZING!

Now, try this harder one:
prove that .999... != 1

 

[Talon02]

Death to this thread.

 

[Chumpman]

Originally posted by: MAME

Originally posted by: Stefan

Originally posted by: MAME

Originally posted by: Stefan
Theoretically, 1 != .999...
Practically, 1 = .999...

you are wrong. prove this statement

X = .999999999999999

1 - X = .000000000000001
1 - 1 = 0

.000000000000001 != 0

therefore X != 1

therefore .999999999999999 != 1

You can't look at it any other way. The 2 numbers are not the same.

I don't want to start talking about limits.

congradulations! You proved that .999999999999999 != 1


THAT'S AMAZING!

Now, try this harder one:
prove that .999... != 1

hahahaha

 

[BigToque]

Originally posted by: MAME

Originally posted by: Stefan

Originally posted by: MAME

Originally posted by: Stefan
Theoretically, 1 != .999...
Practically, 1 = .999...

you are wrong. prove this statement

X = .999999999999999

1 - X = .000000000000001
1 - 1 = 0

.000000000000001 != 0

therefore X != 1

therefore .999999999999999 != 1

You can't look at it any other way. The 2 numbers are not the same.

I don't want to start talking about limits.

congradulations! You proved that .999999999999999 != 1


THAT'S AMAZING!

Now, try this harder one:
prove that .999... != 1

X = .999...

1 - X = .000...0001
1 - 1 = 0

.000...0001 != 0

therefore X != 1

therefore .999... != 1

It is irrelevent how many 9's you add to the end of the number, you are only apporaching 1 and never getting there.

 

[silverpig]

So you have a decimal point followed by an infinite number of zeros, and then a few more zeros, and then a one, and then nothing... Anything seem wrong with that?