Is 1 = 0.9999......

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DrPizza

Administrator Elite Member Goat Whisperer
Mar 5, 2001
49,601
167
111
www.slatebrookfarm.com
Actually you did violate something. 9.9999..... - 0.99999...... is technically undefined. As you cannot do set mathematical actions with infinites. Infinity minus infinity is not zero, it's still infinity. So you cannot perform the mathematical action of 9.9999...... - 0.9999.......

He didn't subtract infinity from infinity. And, problems producing infinity minus infinity are "indeterminate"... many of those problems arise in limit problems and are very easily solved using L'Hopital's Theorem.

Nonetheless, for whichever idiot said you can't perform an algebraic operation an infinite number of times, I blow my nose at you.

.33333333 repeating - .333333333repeating = 0
And, you say it can't be done. Bah. You are just too stubborn to admit that all the math people in this forum (as well as links and references to scholarly sources in mathematics) are correct when they say .999repeating=1


Now, lock the thread (so that I get the last word!)

maybe if we all start calling names and posting prOn in this thread, it'll get locked.....

[edit: grammar]
 

MegaloManiaK

Golden Member
May 27, 2003
1,207
0
0
Originally posted by: Kyteland
Originally posted by: MegaloManiaK
Lock it on up

Please list one good reason why this thread should be locked.

"Because I want to" isn't a good reason.

When you see someone stuck in the mud for hours on end who doesn't know any better than to sit and keep spinning the wheels wouldn't you want to go over and take the keys away or at least help them out.

Same concept,

you=stuck in the mud with this thread
me=gonna come by with a 2x4 and make the hurting stop.

Seriously though, i have no point in this. If ya want to drudge it up every week thats fine by me.

 

RossGr

Diamond Member
Jan 11, 2000
3,383
1
0
Originally posted by: Broohaha
all you atot mth nerds shut up and let this thread DIE

I am not sure I understand the logic of such a post.

You are saying let the thread die, but by your actions you are reviving it. If you really wish to let it die...


DO NOT POST TO IT!
 

bleeb

Lifer
Feb 3, 2000
10,868
0
0
Originally posted by: MegaloManiaK
Originally posted by: Kyteland
Originally posted by: MegaloManiaK
Lock it on up

Please list one good reason why this thread should be locked.

"Because I want to" isn't a good reason.

When you see someone stuck in the mud for hours on end who doesn't know any better than to sit and keep spinning the wheels wouldn't you want to go over and take the keys away or at least help them out.

Same concept,

you=stuck in the mud with this thread
me=gonna come by with a 2x4 and make the hurting stop.

Seriously though, i have no point in this. If ya want to drudge it up every week thats fine by me.

Sometimes you like to watch the guy stuck in the mud and laugh at him. Its the same sort of concept with this thread except not so mean.
 

sxr7171

Diamond Member
Jun 21, 2002
5,079
40
91
Originally posted by: bleeb
Originally posted by: flood 1/3 = 0.3333... 1/3 + 1/3 + 1/3 = 1 0.3333... + 0.3333... + 0.3333... = 0.9999... 1 = 0.9999...
You're WRONG TOO. 1/3 is an exact answer 0.3333... is an approximation Therefore, 1 != 0.9999

Similarly 0.99999.... is also an approximation. In fact what you posted only cemented in mind that 0.99999 = 1.
 

Kyteland

Diamond Member
Dec 30, 2002
5,747
1
81
Originally posted by: bleeb
Originally posted by: MegaloManiaK
Originally posted by: Kyteland
Originally posted by: MegaloManiaK
Lock it on up

Please list one good reason why this thread should be locked.

"Because I want to" isn't a good reason.

When you see someone stuck in the mud for hours on end who doesn't know any better than to sit and keep spinning the wheels wouldn't you want to go over and take the keys away or at least help them out.

Same concept,

you=stuck in the mud with this thread
me=gonna come by with a 2x4 and make the hurting stop.

Seriously though, i have no point in this. If ya want to drudge it up every week thats fine by me.

Sometimes you like to watch the guy stuck in the mud and laugh at him. Its the same sort of concept with this thread except not so mean.

But one of these days all of you "!=" people will become unstuck and the fun will be over.

 

DanTMWTMP

Lifer
Oct 7, 2001
15,908
19
81
you guys are all stupid...who cares?!?!

in some applications, 0.99999... IS 1...and mathematically it's not 1...but conceptually it can be 1...

end of discussion....

it's a simple concept...
 

RossGr

Diamond Member
Jan 11, 2000
3,383
1
0
Originally posted by: sxr7171
Originally posted by: bleeb
Originally posted by: flood 1/3 = 0.3333... 1/3 + 1/3 + 1/3 = 1 0.3333... + 0.3333... + 0.3333... = 0.9999... 1 = 0.9999...
You're WRONG TOO. 1/3 is an exact answer 0.3333... is an approximation Therefore, 1 != 0.9999

Similarly 0.99999.... is also an approximation. In fact what you posted only cemented in mind that 0.99999 = 1.


If .999.... is approximatly 1 there must be an error term, please specify that error. In other words

1- .999.... =?

You sat this number in not zero, so what is it?
 

Ferocious

Diamond Member
Feb 16, 2000
4,584
2
71
Weird...I never seen this thread before.

Anyways the answer is quite simple.

lim_(m --> oo) sum_(n = 1)^m (9)/(10^n) = 1
0.9999... = 1

Thus x = 0.9999...
10x = 9.9999...
10x - x = 9.9999... - 0.9999...
9x = 9
x = 1.


click
 

sxr7171

Diamond Member
Jun 21, 2002
5,079
40
91
Originally posted by: OIKOS
is 1.0000000000000000000000000000000000000000000000000000000001 = 1?

The guy who posted 0.3333....+ 0.3333.....+ 0.3333.... = 0.9999.... = 1
is the same as 1/3 + 1/3 + 1/3 = 0.9999.... = 1
gave me all the proof I need.
The definition of 1/3 is one part of "one" divided into 3 equal parts.


 

bleeb

Lifer
Feb 3, 2000
10,868
0
0
Originally posted by: sxr7171
Originally posted by: OIKOS
is 1.0000000000000000000000000000000000000000000000000000000001 = 1?

The guy who posted 0.3333....+ 0.3333.....+ 0.3333.... = 0.9999.... = 1
is the same as 1/3 + 1/3 + 1/3 = 0.9999.... = 1
gave me all the proof I need.
The definition of 1/3 is one part of "one" divided into 3 equal parts.

BUT... you are losing the accuracy when you convert 0.33333... = 1/3.

EDIT: Also, you are cancelling your proof when you make the statement "... =0.9999... = 1" in that first line.
 

RossGr

Diamond Member
Jan 11, 2000
3,383
1
0
Originally posted by: bleeb
Originally posted by: sxr7171
Originally posted by: OIKOS
is 1.0000000000000000000000000000000000000000000000000000000001 = 1?

The guy who posted 0.3333....+ 0.3333.....+ 0.3333.... = 0.9999.... = 1
is the same as 1/3 + 1/3 + 1/3 = 0.9999.... = 1
gave me all the proof I need.
The definition of 1/3 is one part of "one" divided into 3 equal parts.

BUT... you are losing the accuracy when you convert 0.33333... = 1/3.

EDIT: Also, you are cancelling your proof when you make the statement "... =0.9999... = 1" in that first line.

Bleeb,
You are in fine form today! Is the new goal 2K?

 

sxr7171

Diamond Member
Jun 21, 2002
5,079
40
91
Originally posted by: RossGr
Originally posted by: sxr7171
Originally posted by: bleeb
Originally posted by: flood 1/3 = 0.3333... 1/3 + 1/3 + 1/3 = 1 0.3333... + 0.3333... + 0.3333... = 0.9999... 1 = 0.9999...
You're WRONG TOO. 1/3 is an exact answer 0.3333... is an approximation Therefore, 1 != 0.9999
Similarly 0.99999.... is also an approximation. In fact what you posted only cemented in mind that 0.99999 = 1.
If .999.... is approximatly 1 there must be an error term, please specify that error. In other words 1- .999.... =? You sat this number in not zero, so what is it?

I'm sorry it is actually 1. Just like 0.3333... is 1/3. The thing is that since we can never fully write out the number (fraction) in decimal form I sort of saw it as an approximation but when we write 0.3333... we mean that it goes out infinity number of decimal places, in that sense it really is just 1/3. Similarly when we say 0.9999.... it really is just 1.
 

DanTMWTMP

Lifer
Oct 7, 2001
15,908
19
81
Originally posted by: Ferocious
Weird...I never seen this thread before.

Anyways the answer is quite simple.

lim_(m --> oo) sum_(n = 1)^m (9)/(10^n) = 1
0.9999... = 1

Thus x = 0.9999...
10x = 9.9999...
10x - x = 9.9999... - 0.9999...
9x = 9
x = 1.


click


WELL FOLKS...EVERYONE WAS JUST PWND BY FEROCIOUS' POST..NOW GO AWAY EVERYONE....LOOK @ THE LINK...BREAK YOUR KEYBOARD...DIE YOU STUPID THREAD
 

bleeb

Lifer
Feb 3, 2000
10,868
0
0
Originally posted by: RossGr
Originally posted by: bleeb
Originally posted by: sxr7171
Originally posted by: OIKOS
is 1.0000000000000000000000000000000000000000000000000000000001 = 1?

The guy who posted 0.3333....+ 0.3333.....+ 0.3333.... = 0.9999.... = 1
is the same as 1/3 + 1/3 + 1/3 = 0.9999.... = 1
gave me all the proof I need.
The definition of 1/3 is one part of "one" divided into 3 equal parts.

BUT... you are losing the accuracy when you convert 0.33333... = 1/3.

EDIT: Also, you are cancelling your proof when you make the statement "... =0.9999... = 1" in that first line.

Bleeb,
You are in fine form today! Is the new goal 2K?


Just having fun. I'm bored.
 

RossGr

Diamond Member
Jan 11, 2000
3,383
1
0
Originally posted by: sxr7171
Originally posted by: RossGr
Originally posted by: sxr7171
Originally posted by: bleeb
Originally posted by: flood 1/3 = 0.3333... 1/3 + 1/3 + 1/3 = 1 0.3333... + 0.3333... + 0.3333... = 0.9999... 1 = 0.9999...
You're WRONG TOO. 1/3 is an exact answer 0.3333... is an approximation Therefore, 1 != 0.9999
Similarly 0.99999.... is also an approximation. In fact what you posted only cemented in mind that 0.99999 = 1.
If .999.... is approximatly 1 there must be an error term, please specify that error. In other words 1- .999.... =? You sat this number in not zero, so what is it?

I'm sorry it is actually 1. Just like 0.3333... is 1/3. The thing is that since we can never fully write out the number (fraction) in decimal form I sort of saw it as an approximation but when we write 0.3333... we mean that it goes out infinity number of decimal places, in that sense it really is just 1/3. Similarly when we say 0.9999.... it really is just 1.

The beauty of Math is that we do not have to write out all of the digits to work with the concept. I posted a link to a valid mathematical proof about several pages back.
 

RossGr

Diamond Member
Jan 11, 2000
3,383
1
0
Originally posted by: bleeb
Originally posted by: RossGr
Originally posted by: bleeb
Originally posted by: sxr7171
Originally posted by: OIKOS
is 1.0000000000000000000000000000000000000000000000000000000001 = 1?

The guy who posted 0.3333....+ 0.3333.....+ 0.3333.... = 0.9999.... = 1
is the same as 1/3 + 1/3 + 1/3 = 0.9999.... = 1
gave me all the proof I need.
The definition of 1/3 is one part of "one" divided into 3 equal parts.

BUT... you are losing the accuracy when you convert 0.33333... = 1/3.

EDIT: Also, you are cancelling your proof when you make the statement "... =0.9999... = 1" in that first line.

Bleeb,
You are in fine form today! Is the new goal 2K?


Just having fun. I'm bored.

Me to!
 

TuxDave

Lifer
Oct 8, 2002
10,571
3
71
I thought someone earlier intrduced the idea of a 'dark number' where it's essentially defined as the smallest number greater than zero. And that dark number is the difference between 1 and 0.999...

And that dark number falls under the messed up rules of infinite where if you multiply it against any finite number, it equals itself. If you divide it against any finite number it equals itself.
 

sxr7171

Diamond Member
Jun 21, 2002
5,079
40
91
Originally posted by: bleeb
Originally posted by: sxr7171
Originally posted by: OIKOS is 1.0000000000000000000000000000000000000000000000000000000001 = 1?
The guy who posted 0.3333....+ 0.3333.....+ 0.3333.... = 0.9999.... = 1 is the same as 1/3 + 1/3 + 1/3 = 0.9999.... = 1 gave me all the proof I need. The definition of 1/3 is one part of "one" divided into 3 equal parts.
BUT... you are losing the accuracy when you convert 0.33333... = 1/3. EDIT: Also, you are cancelling your proof when you make the statement "... =0.9999... = 1" in that first line.

Perhaps we don't lose accuracy when we say 1/3 = 0.3333....
I think we're getting more into philosophy now, because I am starting to argue that 1/3 is 0.3333... taken to an infinite number of decimal places. But honestly, I don't know if we can rightfully say that we have a number written to an infinite of decimal places. Perhaps we eventually lose accuracy somewhere along the line, but we cannot say if we will ever approach that point or if that point even exists.

I was just saying that 0.9999... = 1 or is the same as 1. But I guess you could argue that it was unnecessary to point that out if I truly believed they are the same, but I still needed to point it out.
 

bleeb

Lifer
Feb 3, 2000
10,868
0
0
Originally posted by: sxr7171
Originally posted by: bleeb
Originally posted by: sxr7171
Originally posted by: OIKOS is 1.0000000000000000000000000000000000000000000000000000000001 = 1?
The guy who posted 0.3333....+ 0.3333.....+ 0.3333.... = 0.9999.... = 1 is the same as 1/3 + 1/3 + 1/3 = 0.9999.... = 1 gave me all the proof I need. The definition of 1/3 is one part of "one" divided into 3 equal parts.
BUT... you are losing the accuracy when you convert 0.33333... = 1/3. EDIT: Also, you are cancelling your proof when you make the statement "... =0.9999... = 1" in that first line.

Perhaps we don't lose accuracy when we say 1/3 = 0.3333....
I think we're getting more into philosophy now, because I am starting to argue that 1/3 is 0.3333... taken to an infinite number of decimal places. But honestly, I don't know if we can rightfully say that we have a number written to an infinite of decimal places. Perhaps we eventually lose accuracy somewhere along the line, but we cannot say if we will ever approach that point or if that point even exists.

I was just saying that 0.9999... = 1 or is the same as 1. But I guess you could argue that it was unnecessary to point that out if I truly believed they are the same, but I still needed to point it out.

NO. You are losing accuracy.... basically you are making an approximation (0.3333...) equal to something definite (1/3). You're losing accuracy. =)
 

RossGr

Diamond Member
Jan 11, 2000
3,383
1
0
'Cause of this thread, I have modified my sig. Now to see how a mathematician approaches this proof simply click on the link in my sig.
 

sxr7171

Diamond Member
Jun 21, 2002
5,079
40
91
Originally posted by: RossGr
Originally posted by: sxr7171
Originally posted by: RossGr
Originally posted by: sxr7171
Originally posted by: bleeb
Originally posted by: flood 1/3 = 0.3333... 1/3 + 1/3 + 1/3 = 1 0.3333... + 0.3333... + 0.3333... = 0.9999... 1 = 0.9999...
You're WRONG TOO. 1/3 is an exact answer 0.3333... is an approximation Therefore, 1 != 0.9999
Similarly 0.99999.... is also an approximation. In fact what you posted only cemented in mind that 0.99999 = 1.
If .999.... is approximatly 1 there must be an error term, please specify that error. In other words 1- .999.... =? You sat this number in not zero, so what is it?
I'm sorry it is actually 1. Just like 0.3333... is 1/3. The thing is that since we can never fully write out the number (fraction) in decimal form I sort of saw it as an approximation but when we write 0.3333... we mean that it goes out infinity number of decimal places, in that sense it really is just 1/3. Similarly when we say 0.9999.... it really is just 1.
The beauty of Math is that we do not have to write out all of the digits to work with the concept. I posted a link to a valid mathematical proof about several pages back.

Thanks. I think the proof you linked to is a good proper proof. I was wondering if we could see if there was a more intuitive way to see this as well.


Edit: Whoa! I haven't seen that proof before. I thought you linked to the simple one where there's the simple algebraic proof. This one is take going to take me a while to understand, and I think it will be worth understanding it. Math wasn't one of my strong subjects at all. When I see a page with squiggly lines and such it makes me very thankful that I didn't have to learn that stuff and at the same time wonder how much more understanding I would have if I had learn to read the "squiggly lines."

Wait a minute... The second proof was pretty easy to understand. It was a good one too. Sigma notation... it's all coming back to me.
 
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