Math riddle for you guys

chuckywang

Lifer
Jan 12, 2004
20,133
1
0
I realized I made a mistake in the problem. This question showed up in my final this semester. I thought it was pretty neat.

Suppose you are trying to pick the results (win, lose, or tie) of 13 different football games one day. You can have as many submissions as you want. First prize goes to all the people who guess all 13 games correctly. Second prize goes to all the people who guess all but one game correctly. What is the least number of submissions you have to make in order for you to be guaranteed first or second place?

Note there are 3^13 number of different results.
 

mugs

Lifer
Apr 29, 2003
48,920
46
91
Crap, 3 different outcomes for each game and it's still less than 4096?
 

conehead433

Diamond Member
Dec 4, 2002
5,569
901
126
Well you changed the parameters of the problem by including the possibility of a tie. Therefore there are 3 possibilities for each of 13 games. 39 X 13 = 507 minus 1 incorrect game would be 506.

Edit: With only having to get 12 games correct it should only be 39 x 12 = 468. My bad.
 
Aug 10, 2001
10,420
2
0
The probability of getting at least 12 games right is 1/59049, so wouldn't that mean that the number of submissions would need to be at least 59,049?

Adding the "tie" option makes it confusing. I give up.
 

Goosemaster

Lifer
Apr 10, 2001
48,775
3
81
Originally posted by: conehead433
Well you changed the parameters of the problem by including the possibility of a tie. Therefore there are 3 possibilities for each of 13 games. 39 X 13 = 507 minus 1 incorrect game would be 506.

whoops.....I got the same thing


<-----stil out of it from xmas
 

chuckywang

Lifer
Jan 12, 2004
20,133
1
0
Originally posted by: Random Variable
The probability of getting at least 12 games right is 1/59049, so wouldn't that mean that the number of submissions would need to be at least 59,049?

Yes, keep thinking along that track.
 

conehead433

Diamond Member
Dec 4, 2002
5,569
901
126
Originally posted by: conehead433
Well you changed the parameters of the problem by including the possibility of a tie. Therefore there are 3 possibilities for each of 13 games. 39 X 13 = 507 minus 1 incorrect game would be 506.

Edit: With only having to get 12 games correct it should only be 39 x 12 = 468. My bad.


Hopefully this is correct.
 

chuckywang

Lifer
Jan 12, 2004
20,133
1
0
Originally posted by: conehead433
Originally posted by: conehead433
Well you changed the parameters of the problem by including the possibility of a tie. Therefore there are 3 possibilities for each of 13 games. 39 X 13 = 507 minus 1 incorrect game would be 506.

Edit: With only having to get 12 games correct it should only be 39 x 12 = 468. My bad.


Hopefully this is correct.

I can't follow your reasoning and your answer isn't correct.
 

KingofCamelot

Golden Member
Aug 20, 2004
1,074
0
0
36?

I say 36, because if you put win down for both teams in all but one game (12 x 2), and then put tie for all 12 of those games as well, you've covered all your bases to secure second place with only 36 submissions. Atleast that was my logic, its probably flawed though.
 

mugs

Lifer
Apr 29, 2003
48,920
46
91
Originally posted by: chuckywang
Originally posted by: Goosemaster
Originally posted by: chuckywang
Originally posted by: Goosemaster
531441

way less than that.

has anyone gotten it yet?

Someone posted the correct answer but hasn't explained.

So it's either 13, 5 or 96? Those are the only ones I see with no explanation that you haven't shot down yet.


Edit: Unless it's 59049 and you just mean they haven't explained it thoroughly enough...
 

PhilsPhan

Member
Jul 10, 2003
45
0
0
Correct answer is 531441. There are 3 possible outcomes to each game. Therefore you have a 1/3 chance of guessing correctly for each game. Only need 12 games right. Thus it is 1/3^12 *1 (3/3 the last game it doesn't matter if it is right or wrong.)
 
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