Well one way is to use the fact that the power series expansion of arctan(x):
x - x^3/3 + x^5/5 - x^7/7 + ... converges to pi/4 for x = 1. So if you were to calculate enough terms of the summation and then multiplied that by 4, you could get pi to as many terms as you wanted. This method is not very fast though. I found a link that outlines some of the better ones though:
know something really sppoky?
Think of the most important numbers in math, we have e, pi, i, 1, and 0. sure we have some more, but those are the biggies, right.
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